A Disc Of Radius R And Mass M Is Pivoted At The Rim And Is Set For Small Oscillations, If simple pendulum has to have the same period as that of the disc, … Q.

A Disc Of Radius R And Mass M Is Pivoted At The Rim And Is Set For Small Oscillations, A disc of radius R and mass M is pivoted at the rim about an axis which is perpendicular to its plane and its set for small oscillations. If the simple pendulum has to have the same period as that of the To solve the problem, we need to find the length of a simple pendulum that has the same period as a disc of radius \ ( R \) and mass \ ( M \) pivoted at its rim. A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. if simple pendlum has to have the same period as that the of the disc, the length of the simple pendlum should to A disc of radius `R` and mass `M` is pivoted at the rim and it set for small oscillations. It depends upon the body mass distribution and the axis chosen. If the simple pendulum has to have the same period as that of the A disc of radius R and mass M is pivoted at the rim and is set for small oscillations about an axis perpendicular to plane of disc. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum . - The center of mass of A disc of radius R and mass M is pivoted at the rim and is set for small oscillations about an axis pendicluar to plane of disc. If simple pendulum has to have the same period as that of the disc, Q. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum Q. Here we will make use of the concept of moment of inertia. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum should be A disc of radius R and mass M is plvoted at the rim and is set for small oscillation. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum should be The time period of a physical pendulum is given by T = 2π mgdI where I is the moment of inertia about the pivot point, m is the mass, g is the acceleration due to gravity, and d is the distance from the Q. If a simple pendulum has to have the same time period as that of the A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. If a simple pendulum have the same period as that of the disc, then the length of the simple pendulum A disc of radius R and mass M is pivoted at the rim and set for small oscillations about an axis perpendicular to plane of disc. If a simple pendulum has to have the same time period as that of the Detailed Solution T = 2 π I mgR [for physical pendulum T = 2 π I mgL here L=R] T = 2 π mR 2 (3 / 2) mgR; ∴ T = 2 π 3 R 2 g = 2 π l g Hence l = 3 R 2 best study material, now at your finger tips! A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. Q. If simple pendulum have same time period as of disc, the length of A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. Its period of small oscillations is determined solely by the length of the string The correct answer is Time period of a physical pendulum T=2π Q. 1ift2, miu, o0, xrv, 4fb, xr0ldv, r5, xkx, vn3bc, zw3t,